Solved bca assignment

#include<stdio.h>

#include<conio.h>

/*function declaration*/

largest_and_second_largest(int list[],int &largest,int &slargest);

smallest_and_second_smallest(int list[],int &smallest,int &ssmallest);

main()

Function in C++ to find the string length:

/*function to find the string length*/

int mystrlen(char str[]) /* int type function, it will accept an array of characters and return total number of characters */

/*Program to print the contents of a double dimensional array in matrix format.*/

#include<iostream.h>

void main()

{

          int a[10][10]; /*two dimensional array for matrix representation*/

          int i,j;

          int row,col;

          cout<<”Enter row and column of a matrix (up to 10): “;

          cin<<row<<col;

cout<<”Enter the elements for the”<<row<< “X”<<col<<” matrix : ” <<endl;

/*store elements in two dimensional array*/

/*Program to print the month of a year*/

#include<iostream.h>

void main()

{

          int month;

          char monthName[15];

cout<<”Enter month number : “<<endl;

cin>>month;

switch (month)

{

There are tow types of if….else statements in C++ which are explained below.

Simple if….else statement

Syntax: if(expression or condition)

          { statement 1;

             statement 2;

          }

          else

          { statement 3;

             statement 4;

          }

A major factor in the invention of Object-Oriented approach is to remove some of the flaws encountered with the procedural approach. In OOP, data is treated as a critical element and does not allow it to flow freely. It bounds data closely to the functions that operate on it and protects it from accidental modification from outside functions. OOP allows decomposition of a problem into a number of entities called objects and then builds data and functions around these objects. A major advantage of OOP is code reusability.

Objects

a) Difference between Latch and flip flop

Latches are Level Sensitive, while Flip-Flops are Edge  Sensitive.
A positive level latch is transparent to the positive level(enable), and it lathes the final input before it is changing its level(i.e. before enable goes to '0' or before the clock goes to -ve level.
A positive edge flop will have its output effective when the clock input changes from '0' to '1' state ('1' to '0' for negedge flop) only.
For posedge flop check out the Morris mano book (digital design), in that he gave how the flop behaves with respect to an edge. (Explained with Gate level logic diagram). This will gives you a clear picture of Flop.