Friday 1 March 2013

18:02 -

Perform binary subtraction a) (10110)2 – (11000)2 b) (110110)2 – (111010)2 c) (00100)2 – (100100)2 d) (11110)2 – (00100)2 e) (11111)2 – (110011)2


a)         Using 1’s Complement method (because subtrahend is larger)
  10110(2)         
+00111(2)   (1’s complement of 11000)      
  11101(2)     Answer is negative and is in 1’s complement form
-00010(2)    Answer
                                                                      
                                                           
           

b)         Using 1’s Complement method (because subtrahend is larger)
  110110(2)      
+000101(2)   (1’s complement of 111010)
  111011(2)     Answer is negative and is in 1’s complement form
-000100(2)    Answer
                                                                      
          




c)         Using 1’s Complement method (because subtrahend is larger)
    00100(2)       
+011011(2)   (1’s complement of 100100)
  011111(2)     Answer is negative and is in 1’s complement form
-100000(2)    Answer











d)         Simple method (because subtrahend is smaller)
    11110(2)       
  - 00100(2)   
    11010(2)       Answer






e)         Using 1’s Complement method (because subtrahend is larger)
    11111(2)       
+001100(2)   (1’s complement of 110011)
  101011(2)     Answer is negative and is in 1’s complement form
-010100(2)    Answer